
Ask B&H Photo! - PentaxForums.com
Aug 27, 2019 · Ask B&H Photo! - Have a specific question about current Pentax products or accessories? Ask our specialist from B&H!
B&H/Canon Lens FD 50mm F1.8 SC (1973) Front Element Removal
Apr 26, 2023 · PentaxForums.com → Pentax Lenses and Accessories → Pentax SLR Lens Discussion → B&H/Canon Lens FD 50mm F1.8 SC (1973) Front Element Removal Page 1 of 2 1 2 ... Page 1 of …
BhPhoto open box, any experience? - PentaxForums.com
Mar 11, 2017 · Just wanted to get thoughts from anybody who might have had experience buying open box from B&H. It says full manufacturer's warranty, but in box
B&H Price Change Policy Question - PentaxForums.com
Sep 7, 2014 · Anyone know what B&H's policy on price matching when they drop the price? I bought the K3 package with grip and flash for $1296.99 on 8/11/14. I
How to get B&H Customer Service to Respond to my issue?
Jun 21, 2021 · Hi Chuck-B&H and/or henryp, I am having an issue for an order I placed at B&H, which was written up here: Venting - The saga of my wayward
Lens rebates! US Pentax Deal Roundup: Week of September 8, 2025
Sep 8, 2025 · Welcome to this week's roundup of top US Pentax deals! A host of hefty rebates on star lenses and more are currently available:
Old B&H catalog archive thread - PentaxForums.com
Mar 11, 2021 · I'd like to publish links to older PDF catalog from B&H. It's quite interesting to see all film SLR companies and products together. Some catalogs
operator algebras - Strong and $\sigma$-strong topology on $B (H ...
Apr 19, 2020 · I want to prove that on the unit ball in $B (H)$, these two topologies are the same. In the proof it is written that the seminorms defining $\sigma$ -strong topology is the uniform limit of …
The Pentax Marketplace | Buy & Sell Pentax Cameras and ... - Pentax …
Jan 22, 2026 · Photographic Equipment for Sale - Pentax classifieds - sell your used Pentax gear, or buy photographic equipment from others in our fantastic
Normal states are dense in $B (H)$ - Mathematics Stack Exchange
Dec 15, 2014 · Then $$ \overline {T (H)}^ {w}=T (H)''= (\mathbb C I)'=B (H), $$ where the first equality is von Neumann's Double Commutant Theorem. Note that the assertion as stated in the title cannot be …